word problem????????

Question by 333kelly333 Reward: 25 Pond Points + 10 Knowledge Tokens Status: Answer selected by AnswerPond
the number of quarters a person has is seven times the number of dimes. The value of the dimes exceedes the value of the quarters by two dallars. How much of each coin does the person have?



Reply from drk_phoenix Accepted answer! User Rating:  30 Knowledge Tokens

I have good news and bad news... The good news is that this problem is solvable. The bad news is that this problem doesn't really work in the real world.

You need to set up two equations for this problem, one relating the number of dimes to quarters:

7d = q (where d is the number of dimes and q is the number of quarters)

And the other relating the values of the total coins:

10d = 25q +200

Then substitute from the first equation:

10d = 25(7d) + 200
d = -1.2121212
q = 7(-1.21212) = -8.48484848

So, unless you have -1.121212 of a dime, and -8.484848 quarters lying around the problem doesn't really make sense.
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